2x^2-16x=40

Solution for 2x^2-16x=40 equation:

2x^2-16x=40

We move all terms to the left:

2x^2-16x-(40)=0

a = 2; b = -16; c = -40;
Δ = b2-4ac
Δ = -162-4·2·(-40)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-24}{2*2}=\frac{-8}{4}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+24}{2*2}=\frac{40}{4}
=10
$